A train is travelling at aseep of 90 k.m h-1 . bracks are applied so as to produce uniform acceleration of 0.5. find how far the train willgo before it is brought torest.
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Explanation:
Given that,
Acceleration a=−0.5m/s2
Speed v=90km/h=25m/s
Using equation of motion,
v=u+at
Where,
v = final velocity
u = initial velocity
a = acceleration
t = time
Put the value into the equation
Finally train will be rest so, final velocity,v=0
0=25−0.5t
25=0.5t
25=0.5t
t=0.525
t=50 sec
Again, using equation of motion,
S=ut+21at2
Where, s = distance
v = final velocity
u = initial velocity
a = acceleration
t = time
Put the value into the equation
Where S is distance travelled before stop
s=25×50−21×0.5×(50)2
s=625 m
So, the train will go before it is b
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