Question

A train is travelling at speed 90 km per hour . Breaks are applied so as to produce uniform acceleration of -0.6 metre per second ^2. Find how far train will go before it is brought to rest

Answer 1

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Answer 2

Answer:

Distance, s = 520.8 m

Explanation:

It is given that,

Initial speed of train, u = 90 km/h = 25 m/s

When brakes are applied, the uniform acceleration of the train is -0.6 m/s². We have to find the distance covered by the train before it come to rest.

Using third equation of motion :

$v^2-u^2=2as$

$0-(25\ m/s)^2=2\times -0.6\times s$

s = 520.8 m

So, the train will go 520.8 m before coming to rest. Hence, this is the required solution.