A train is travelling at speed 90 km per hour . Breaks are applied so as to produce uniform acceleration of -0.5 metre per second ^2. Find how far train will go before it is brought to rest
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- v equals 0 because of rest.
- u equals 90*5/18=25m/s
- v^2=u^2+2as
- 0=25^2*-0.5*2*s
- 0=625-1s
- -625=-s
- thus s=625 m
- I thinks it's correct .
- is it helpful
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