Question

A train is travelling at the rate of 45 km/hr.How many seconds it will take to cover a distance of 4/5 km?​

Answer 1

Answer:

64 sec

Step-by-step explanation: first of all its velocity = 45 km hr⁻¹ or 25/2 m sec⁻¹

distance in mtr = 4/5 x 1000 = 800 mtr

speed = dist / time ⇒ time = dist / speed = 800 x 2 / 25 =  64 sec

Answer 2

SOLUTION:-

Given:

A train is traveling at the rate of 45km/hr.

To find:

The second it will take to cover a distance of 4/5 km.

Explanation:

We find time,

So, we know that, Time equal to;

$\frac{Distance}{Time}$

1 hour= 60 minutes

1 hour= 60×60= 3600 seconds.

According to the question:

$= > \frac{ \frac{4}{5} }{45} hr \\ \\ = > \frac{4 \times3600}{ 5\times 45} seconds \\ \\ = > \frac{4 \times 80}{5} seconds \\ \\ = >( 4 \times 16) \: seconds \\ \\ = > 64 \: seconds$

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