Question

a train is travelling at the speed of 180 kilometre per hour brakes are applied so as to produce a uniform acceleration of 1 metre per second square find how far the train will go before it is brought to rest​

Answer 1

Answer:

u=180km/h

180×5/18

=50m/s

a=1m/s^2

v=0

1st equation of motion

v=u+at

0=50+t

t=50s

s=ut+1/2at^2

s=50×50+1/2×1×(50)^2

s=2500+1250

s=3750m

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Answer 2

Answer:

1250 metres

Explanation:

Velocity of the train is 180 km/hr which is 50 m/s ( mutiply the speed by 5/18 ).

Therefore, u = 50 m/s and v i.e the initial velocity will be 0 m/s as the train will be at rest after a certain period of time.

So, we have,

$v = 0 \ m/s\\u = 50 \ m/s\\a = -1 \ m/s$

The accleration is -1 m/s^2 because the velocity will decrease as the brakes are applied. The change in velocity will be negative.

Using,

$v^2 = u^2 + 2as$

We solve for s,

$0 = 2500 + 2(-1)s\\2s = 2500\\s = 1250$

Hence, the displacement ( s ) is 1250 m.