Question

A train is travelling with 10 m/s with a constant acceleration of lm/s, in the direction of
velocity, for 20 sec. How far will it travel during this time?​

Answer 1

Explanation:

Given,

Initially velocity, u = 10m/s

Acceleration, a = 1m/s²

Time, t = 20s

Let distance be S.

Using formula,

S = ut + 1/2at²

S = 10×20 + 1/2 × 1 × 20 × 20

S = 200 + 200

S = 400m

The train will travel 400m during this time.

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Answer 2

Answer:

400 m is the distance

Explanation:

acceleration - 1m/s

u-10m/s

t - 20 sec

s=ut+ 1/2at^2

= 20(10)+1/2(20)^2(1)

=400/2+200

=400m