a train is travelling with a velocity of 36 km per hour what should be the acceleration on it so that it may reach a point 10km ahead in 8 minutes what will be its velocity on reaching that.
answer soon pls
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initial velocity, u=40 km/h
distance, s=10 km
time, t=8 minutes
t=8
60
hours
t=
2
15
hours
(1) s=ut+
1
2
at
2
10=40×
2
15
+
1
2
a×
(
2
15
)
2
10−
16
3
=
2
225
a
2
225
a=
30−16
3
a=
14
3
×
225
2
a=525 km/
h
2
(2) v=u+at
v=40+525×
2
15
v=40+70=110 km/h
hope this answer will help you.....
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distance, s=10 km
time, t=8 minutes
t=8
60
hours
t=
2
15
hours
(1) s=ut+
1
2
at
2
10=40×
2
15
+
1
2
a×
(
2
15
)
2
10−
16
3
=
2
225
a
2
225
a=
30−16
3
a=
14
3
×
225
2
a=525 km/
h
2
(2) v=u+at
v=40+525×
2
15
v=40+70=110 km/h
hope this answer will help you.....
Plzzz mark as brainiest
bhargavkokkulapazmp4:
hlo
recheck the answer
U=36km
not 40 km
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