Question

a train is travelling with a velocity of 36 km per hour what should be the acceleration on it so that it may reach a point 10km ahead in 8 minutes what will be its velocity on reaching that.

answer soon pls

Answer 1

initial velocity, u=40 km/h

distance, s=10 km

time, t=8 minutes

t=8

60

 hours

t=

2

15

 hours

(1) s=ut+

1

2

at

2

10=40×

2

15

+

1

2

a×

(

2

15

)

2

10−

16

3

=

2

225

a

2

225

a=

30−16

3

a=

14

3

×

225

2

a=525 km/

h

2

(2) v=u+at

v=40+525×

2

15

v=40+70=110 km/h

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