Question

A train is travelling with a velocity of 90 kilometre per hour. Brakes are applied so as to produce a uniform acceleration of -0.5 metre per second square. Find how far train will go before it is brought to rest.​

Answer 1

Explanation:

u= 90×5/18 = 25 m/s

a=-0.5 m/s^2

v=0

s=?

v^2=u^2+ 2as

0^2= (25)^2 + 2×(-0.5)s

0^2=625 - s

s=625 m