a train is uniformly accelerated and passes successive kilometre stone with velocities of 18 km.p.h and 36 km.p.h respectively .calculate the velocity,when it passes the third kilometre stone.also find the time taken for each of these two intervals kilometre.
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Answer:V=13.22m/s ,T1=133.4 &T2=86.13
Explanation:
Given that
Initial velocity U=18km/hr=18*5/18=5m/s.
Final velocity
V=36km/hr=36*5/18=10m/s.
a=?
V3=?
V^2-U^2=2as.
10^2-5^2=2*a*1000.
a=0.375m/s*s.
V3^2-U^2=2as.
V3^2=2as+U^2.
V3^2=2*0.375*2000+5^2.
V3=√(2*0.375*2000+25).
V3=13.22m/s..
Time interval
V=U+aT1
T1=V-U/a
T1=(10-5)/0.375=133.4sec.
T2=(13.2-10)/0.375=86.13sec.
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