A train leaves a city P at 12:00 O' clock morning and reaches city Q at 4:00 A.M.. Another train leaves city Q at 2:00 A.M. and reaches the city P at 5:30 A.M.. At what time do the two trains cross each othera) 2:45 AM b) 2:56 P.M. c) 2:56 A.M. d) 3:00 A.M.
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Total distance PQ = x units
At 2 A.M,
train P, distance covered = x/2, with speed = x/4
train Q, Speed = x/(3.5)
time after 2 A.M, they'll meet at (x/2)/(x/4 + x/3.5) = 70/75 * 60 = 56 mins.
Therefore, 2 A.M + 56 min = 2:56 A.M ans.
At 2 A.M,
train P, distance covered = x/2, with speed = x/4
train Q, Speed = x/(3.5)
time after 2 A.M, they'll meet at (x/2)/(x/4 + x/3.5) = 70/75 * 60 = 56 mins.
Therefore, 2 A.M + 56 min = 2:56 A.M ans.
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