A train leaves at 5:58 a.m. Can it be rounded off to 6:00 a.m.True or false
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Speed of fir train =60 kmph
Speed of second train = 75 kmph
First train leaves at 5 AM and the second train at 6:30AM I.e. 1 1/2 hrs after
distance traveled by first train in 1 1/2 hrs or 3/2 hrs= 60x3/2=90 km
relative velocity of second train wrt first train =
75–60=15Kmph
hence time taken By second train to cover the gap of 90 km=90/15=6 hrs
Time at which second train catches the first =6:30+6=12:30. PM
distance from the station=75x6=450 km
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