A train leaves calcutta at 7.30 am and travels 40 km an hour, another train leaves calcutta at noon and travels 64 km an hour, when and where will the second train overtake the rst?
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Let the trains meet 'x' hours after the start of second train
The first train has traveled x + 4 hrs 30 mins = x + 4 30/60 = x+ 9/2 hrs
(x + 9/2) * 40 = x * 64
40 x + 180 = 64 x
24 x = 180
x = 180/24 = 7 hrs 30 mins (after 12 noon)
Thus the trains meet at 7.30 p.m (evening)
Distance traveled = ( x + 9/2)* 40 = ( 7 1/2 + 9/2) * 40 = 12*40 = 480 kms
Thus the trains meet at 7.30 P.M after travelling 480 km.
Hope it helps.
The first train has traveled x + 4 hrs 30 mins = x + 4 30/60 = x+ 9/2 hrs
(x + 9/2) * 40 = x * 64
40 x + 180 = 64 x
24 x = 180
x = 180/24 = 7 hrs 30 mins (after 12 noon)
Thus the trains meet at 7.30 p.m (evening)
Distance traveled = ( x + 9/2)* 40 = ( 7 1/2 + 9/2) * 40 = 12*40 = 480 kms
Thus the trains meet at 7.30 P.M after travelling 480 km.
Hope it helps.
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