A train leaves kanniyakumari for warangal on tuesday at 10:30 a.m. if warangal is 1586 km from kanniyakumari,when will it reach there if its speed is 39 km/hr?
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Answered by
1
Answer:
speed=distance/time
39=1586/time
39*time=1586
time=1586/39
time=40.6hr
Answered by
0
Speed=distance/time
Time=distance/speed
Time=1586/39
40.66 hr
So,it will reach on Thursday ,3:10....
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