Question

A train leaves Station A at a constant speed and arrives at Station B in 8 hours. A second train leaves Station A at a constant rate of 40 mph and arrives at Station B in 10 hours. What was the constant speed of the first train?​

Answer 1

Answer:

40÷10=4 m/h in one hour

4×8=32 m/h

the first train came at a constant speed of 32 m/h