A train leaves station A to station B. The train travels along a straight line without any halts between the stations. During the first and the last 200m the train has uniform acceleration and retardation both 1m/s2 respectively . For the rest of the journey the trains maintains uniform speed. Calculate the average speed of the train for the journey given the total distance between A and B is 4km.
Answers
Answer:
18.18 m/s
Step-by-step explanation:
A train leaves station A to station B. The train travels along a straight line without any halts between the stations. During the first and the last 200m the train has uniform acceleration and retardation both 1m/s2 respectively . For the rest of the journey the trains maintains uniform speed. Calculate the average speed of the train for the journey given the total distance between A and B is 4km.
Train starts from Rest
and Travels 200 m with acceleration = 1m/s²
Using V² - U² = 2aS
=> V² = 2*1 * 200
=> V = 20 m/s
Distance travelled with 20 m/s = 4000 - 200 - 200 = 3600m
Time = 3600/20 = 180 sec
Time for first 200 m Using V = U + at = 20/1 = 20 sec
Time For LAst 200 m = 20 sec
Total Time = 180 + 20 + 20 = 220 sec
Total Distance = 4km = 4000m
Average speed = 4000/220 = 200/11 = 18.18 m/s
Answer:
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I was asking you
Step-by-step explanation:
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