Question

A train leaves the city at 2 pm. A second train leaves the city at 4 pm and follows the first train. The
second train's speed is 32 km/h faster than the first train's speed. If the second train overtakes the
first train at 8 pm, find the speeds of both the trains.​
STEP BY STEP EXPLANATION ​

Answer 1

Answer:

Step-by-step explanation:

v = the speed of the first train

v + 32 = the speed of the second train

Train 1 = 8 - 2 = 6 hr the time of the first time

Train 2 = 10 - 4 = 6 hr the time of the second time

Since both trains travel the same distance we have:

v Train 1 = (v + 32)Train 2 (we use the formula distance = speed × time)

8 v = 2 × (v + 32)

Answer 2

Answer:

64 km/hr , 96 km/hr

Step-by-step explanation:

First train =

second train = (x+32)

the first train overtakes the first train at 8p.m

so, first train leaves city at 2pm 8-2=6

second train leaves city at 4pm 8-4=4

6x=4(x+32)

=6x=4x+128

6x-4x=128

=2x=128

x=64

First Train = 64km/hr

Second train = 64+32 = 96km/hr