Question

A train leaves the station at 5 am at 60 kmph. Another train leave the same station at 6:30 am at 75 kmph and travels in the direction of the first train. At what time and at what distance from the station will they meet?​

Answer 1

Step-by-step explanation:

Speed of fir train =60 kmph

Speed of second train = 75 kmph

First train leaves at 5 AM and the second train at 6:30AM I.e. 1 1/2 hrs after

distance traveled by first train in 1 1/2 hrs or 3/2 hrs= 60x3/2=90 km

relative velocity of second train wrt first train =

75–60=15Kmph

hence time taken By second train to cover the gap of 90 km=90/15=6 hrs

Time at which second train catches the first =6:30+6=12:30. PM

distance from the station=75x6=450 km

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