Question

a train leaves the station at 5am at 60kmphr another train leave the same station at 6.30am at75kmph and travels in the direction of the first train. at what time and at what distance from the station will they meet​

Answer 1

Answer:

Answer

Distance=Speed×Time

When speed is 40 kmph

Distance traveled by car =40×9

                                         =360 km

When speed is 60 kmph

Time taken to complete the journey =  

60

360

​  

 

                                                            =6 hours

Step-by-step explanation:

ok

Answer 2

Answer:

The train leaving at 3.00 p.m. travels for two hours before the second train leaves station A. During those two hours the first train covers 2h⋅60kmh=120km . Thus the second train starts out 120km behind the first train.

To find the number of kilometers traveled when we first find the number of hours traveled before the two trains meet, let's call it x. This happens when:

120km+60kmh⋅x=75kmh⋅x

⇒120km=15kmh⋅x

⇒x=120km15kmh=120km15km⋅h=8h

Notice how you can check if what you are doing makes sense because we get the right unit of measurement, hours, when we solve for the answer.

So it takes 8 hours before the trains are at the same spot. This gives us that the first train traveled; 120km+60kmh⋅8h=120km+480km=600km

and that the second train traveled; 75kmh⋅8h=600km

The above are off course equivalent but this is again a good opportunity to check the consistency of what you are doing.

Step-by-step explanation:

hope it helps!