A train left a station at 8:35 a.m. and arrived at its destination at 3:12 p.m. How long did the journey take?
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Answered by
84
8:35 a m
(3:12+12:00) p m
the time duration is=15:12
- 8:35
ans/ 6 hours 37 minute
(3:12+12:00) p m
the time duration is=15:12
- 8:35
ans/ 6 hours 37 minute
ZeetAshrabi:
Thank you so much.. It helped me a lot
Answered by
8
Answer:
The duration of the journey takes 6 hours, 37 minutes, and 0 seconds.
Step-by-step explanation:
The train left the station at = 8.35 am
Destination of the train = 3.12 pm
Calculate the time duration:
Subtract the starting time - destination time:
= 8.35 am - 3.12 pm
Breaking in time laps:
8:35 am - 9:00 am = 25 min
9:00 am - 12:00 pm = 3 hour
12:00 pm - 3:00 pm = 3 hour
3:00 pm - 3:12 pm = 12 min
Add all hours and min:
= 25 min + 3 hour + 3 hour + 12 min
= 6 hour + 37 min
Therefore, the time taken in the journey is 6 hours 37 min.
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