Question

A train left Stenworth at 13 20 to travel the 50 km to Beedtown. The train travelled at an average speed of 40km/h. Calculate the time at which the train arrived at Beedtown.

Answer 1

Distance to travel = 50km
Speed during the journey = 40km/h

$Speed= \frac{Distance}{Time}$
$40= \frac{50}{t}$
$t=1.25$ hours
That means an hour and a quarter

The time it departuerd was 13.20
Adding 1 hour 25 minutes to it becomes 14.45

Answer 2

speed =distance /time ;
time = distance /speed ;
time = 50/40
= 1.25
time taken = 13:20 + 1:25
=14:45

answer is 14:45