Question

A train length 50m is moving with a constant speed of 10m/s. Calculate the time taken by the train to cross an electric pole and a bridge of length 250m.(5s,10s)

Answer 1

Answer:

I have tried to solve. May tis will help you.

If incorrect then sorry...

Explanation:

In the first case Let us assum that pole is moving with 10m/s and train is in rest.

time taken to cross the train = length of train / speed

= 50/10

= 5s

In second case we add length of both and will consider as distance travelled.

time taken to cross bridge = (250+50) /10

= 300/10

= 30 s

Answer 2

Hello mate..

Here Is Your Answer:

GIVEN:

Length of the train = s = 50m.

Speed of the train = v = 10m/s.

Therefore,

time taken to cross the electric pole:

$\bold{t = \frac{s}{v} = \frac{50}{10}} \\ \bold{ = 5s}$

Distance travelled while crossing the bridge

→length of train + lenght of the bridge.

=> 50 + 250 = 300m.

Time taken to cross the bridge

$\bold{=> \frac{300m}{10m/ s} } \\ \bold{ = 30 \: seconds.}$

HOPE THIS HELPS YOU..