A train m leaves meerut at 5
a.M. And reaches delhi at 9
a.M. Another train leaves delhi at 7a.M. And reaches meerut at 10.30
a.M. Atwhat time do the two trains cross each other?
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Train M leaves Meerut at 5 A.M. and reaches Delhi at 9 A.M. Another train leaves Delhi at 7 A.M. and reaches Meerut at 10.30 A.M. At what time do the two trains cross each other?
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14 ANSWERS

Niharika Sen, Wannabe Globe Trotter who knows a bit about Maths, and Life.
Updated Apr 12, 2018 · Author has 58 answers and 53.4k answer views
Time taken by first train to cover the distance = 4 hrs. Similarly, time taken by the second train to traverse the same distance = 3.5 hrs.
Thus, the ratio of their speeds = (1 / 4) : (1 / 3.5) = 7 : 8.
Let their speeds be 7X km/hr and 8X km/hr respectively. Thus, D = 4 x 7X = 28X.
At 7 AM, when the second train starts its journey, distance already covered by first train = 14X. Therefore, at 7 AM, the distance between the two trains is 28X - 14X = 14X.
Time taken by the trains to meet = Distance between them / Relative Speed = 14X / (7X + 8X) = 14 / 15 hours = 14 / 15 x 60 minutes = 56 minutes.
Thus, the trains will meet 56 minutes after 7AM, i.e., at 7 : 56 AM.
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14 ANSWERS

Niharika Sen, Wannabe Globe Trotter who knows a bit about Maths, and Life.
Updated Apr 12, 2018 · Author has 58 answers and 53.4k answer views
Time taken by first train to cover the distance = 4 hrs. Similarly, time taken by the second train to traverse the same distance = 3.5 hrs.
Thus, the ratio of their speeds = (1 / 4) : (1 / 3.5) = 7 : 8.
Let their speeds be 7X km/hr and 8X km/hr respectively. Thus, D = 4 x 7X = 28X.
At 7 AM, when the second train starts its journey, distance already covered by first train = 14X. Therefore, at 7 AM, the distance between the two trains is 28X - 14X = 14X.
Time taken by the trains to meet = Distance between them / Relative Speed = 14X / (7X + 8X) = 14 / 15 hours = 14 / 15 x 60 minutes = 56 minutes.
Thus, the trains will meet 56 minutes after 7AM, i.e., at 7 : 56 AM.
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