Question

A train meets two accidents in it journey. First accident happen at 150 km from starting point which reduces train speed to 2/3 rd of original speed. Second accident happen 200 km from first accident, which reduces its speed to 1/3 of original speed. And train reaches the destination 9 hour late.Had both accident happened 50 km farther train would have reached 2 hour earlier than the last one. Find original speed

Answer 1

the speed will be 87.5kmph ,pls check if ans is correct i may explain then

Answer 2

Answer:

25/7 kmph

Step-by-step explanation:

• Let the speed of train be x
• Let the distance after second crash be d
• according to question we have,
• (150/x+(200/(2x/3))+(d/(x/3)))-(200/x+(250/(2x/3))+((d-50)(x/3)))=7
• 150/x+600/2x+3d/x-200/x-750/2x-3d/x+150/x=7
• 100/x-150/2x=7
• taking lcm,
• 50/2x=7
• 2x=50/7
• x=25/7km per hour.