Question

A train met with an accident
50km away from Ananipur
station. It completed the remain
ing journey at s'n of the
previous epeed and reached
Bar mala station how 12 in
late. Had accident taken place
60 km further it would have
been only 3 hourjoie
1) What is the normal speed of
train ?
in what is the distance between
Anantpur and Barmula 2​

Answer 1

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YOUR ANSWER IS

Train proceeds at 3/4 S where S is his usual speed means 1/4 decrease in the speed which will lead to 1/3 increase in the time.

[ As S *T = D, Speed is inversely proportional to time when distance is constant].

Now, the main difference come in those 24 km and the change in difference of time = 35 - 25 = 10 m

= 1 / 3 *T = 10 where T is the time required to cover the distance of (50 - 74) = 24 km

T = 30 min = 0.5 hours

Speed of the train = 24 / (0.5) = 48 kmph