A train moves from one station to another in two hours time. Its speed-time graph during the motion is shown in Fig. (i) Determine the maximum acceleration during the journey (ii) Also calculate the distance covered during the time interval from 0.75 hour to 1 hour.
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Answer:
Maximum acceleration will occur in the region with maximum slope.
From the given curve region CD is having the maximum curve.
Thus, maximum acceleration=
change in distance
change in velocity
=
0.25
60−20
=160
Now, total area under the curve between 0.75 to 1.00 hrs is given by
(
2
1
×0.25×40)+(20×0.25)=10km
Explanation:
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