Question

a train moves from rest to a speed of 2.5m/s in 3.o seconds what is its acceleration​

Answer 1

Answer :-

Given :-

• Initial velocity = 0 ( starting from rest )
• Final velocity = 2.5 m/s
• Time = 3 seconds

To Find :-

• Acceleration

Solution :-

We know that,

a = ( v - u ) / t

where :

• a is acceleration.
• v is final velocity.
• u is initial velocity.
• t is time taken.

Substituting the values in formula :-

→ a = 2.5 - 0 / 3

→ a = 2.5 / 3

→ a = 0.833

Acceleration = 0.833 m/s²

Answer 2

Step-by-step explanation:

Given Information -

• Initial velocity (u) =0m/s (rest)
• Final velocity (v) = 2.5m/s
• Time (t) = 3m/s

ㅤ

To Find -

• Acceleration (a)

ㅤ

Solution -

What to do?

• To find the acceleration with the given information, we'll follow the formula of Velocity Time Relation and will replace the value with the formula to attain our required solution.

ㅤ

Formula to be Implemented -

• ${a=\frac{v-u}{t}}$

ㅤ

Answer -

• ${a=\frac{2.5-0}{3}}$

• ${a=\frac{25}{10×3}}$

• ${a=\frac{25}{30}}$

• a= 0.833

Hence,acceleration is 0.833m/s² .