Question

A train moves from rest to a speed of 25 m/s in 30.0 seconds. What is its acceleration?

Answer 1

Answer:

acceleration=change in velocity÷time=25-0÷30=0.83m/seconds

Explanation:

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Answer 2

Given:

The Initial velocity of train (u)= 0 m/s (as train was at rest initially)

Final velocity of trian (v) = 25 m/s

Time in which train achieves its maximum speed (t) = 30 s

To find:

Acceleration of train =?

Solution:

• Acceleration of the train can be found by dividing the difference between final and initial velocity with the time it takes to achieve this velocity.
• The unit of acceleration is meter/second²
• Apply the following formula to find the acceleration of train:

    => Acceleration of train = (Final velocity - Initial velocity) ÷ Time

    => Acceleration of train = $\frac{v-u}{t}$

    => Acceleration of train = $\frac{25}{30}$

    => Acceleration of train = $\frac{5}{6}$ m/s² or 0.833 m/s²

Hence, the train is accelerating at 0.833 m/s².