A train moves from rest to a speed of 25 m/s in 30 seconds. What is the magnitude of its acceleration?
Answers
Answer:
Explanation:
Given,
Initial velocity of bike, u = 0 m/s (As starts from rest)
Final velocity of bike, v = 25 m/s
Time taken by bike, t = 30 seconds
To Find,
Acceleration by bike, a
Formula to be used,
1st law of motion,
v = u + at
Solution,
Putting all the values, we get
v = u + at
⇒ 25 = 0 + a × 30
⇒ 25 = 30a
⇒ 25/30 = a
⇒ a = 0.83 m/s²
Hence, the acceleration is 0.83 m/s².
Given that , A train moves from rest to a speed of 25 m/s in 30 seconds .
Exigency To Find : The magnitude of Acceleration of train ?
⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀
⠀⠀⠀⠀⠀⠀⠀⠀⠀Given that ,
⠀⠀▪︎⠀The initial velocity ( u ) of train is 0 m/s [ as , train starts from rest ] .
⠀⠀▪︎⠀The final velocity ( v ) of train is 25 m/s .
⠀⠀▪︎⠀Total Time taken ( t ) is 30 seconds .
⠀⠀⠀⠀⠀⠀⠀⠀⠀¤ Finding Magnitude of Acceleration of Train :
⠀⠀⠀Here , v is the final velocity , u is the Initial velocity , t is the total time taken and a is the Acceleration.