Question

A train moves from station A to station B with a speed of 60 km/h and returns from B to A with a speed of 40km/h . find 1)average speed 2) average velocity of the train​

Answer 1

Answer:

Net displacement of the train in coming back to the first station is zero i.e. S=0 .

Average velocity V

avg

=

t

S

=0

Average speed of the train when in moving equal distances is given by ∣V∣

avg

=

v

1

+v

2

2v

1

v

2

⟹ ∣V∣

avg

=

40+60

2×40×60

=48 km/h

Answer 2

Answer:  i will answer this questation

Explanation:

Let the distance between the stations A and B be x km.

Time taken by the train to move from A to B = x40 h

And, time taken to move from B to A = x60 h.

Total distance travelled = 2 xkm.

Initial and final positions are the same and so the total displacement becomes zero and hence average velocity is zero.

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