a train moves in north direction with a speed of 108kmph .Find the amount of induced emf generated between 2 wheels if length of excel is 2m . Assuming that vertical component earths magnetic field is 8.0×10^5 wbpm^2
Answers
Question :
A train moves in north direction with a speed of 108 kmph .Find the amount of induced emf generated between 2 wheels if length of excel is 2m . Assuming that vertical component earths magnetic field is 8.0×10⁵ wbpm²
Given :
- Speed of train = 108 kmph
- Iength of exceI = 2 m b/w 2 wheeIs.
- Magnetic fieId of verticaI component earth = 8.0 × 10⁵ wbpm²
To find :
- Amount of induced emf generated
SoIution :
⇒ Speed = 108 kmph = 108 × (5/18) = 30 mps
⇔ Induced emf = BIV
Where :
- B refers to magnetic fieId component
- I refers to Iength of exceI
- V refers to veIocity/speed
⇒ Induced emf = 8 × 10⁵ × 2 × 30
⇒ Induced emf = 48,000,000 V
⇒ Induced emf = 48,000 mV
∴ Amount of induced emf generated = 48,000 mV
Question :
A train moves in north direction with a speed of 108 kmph .Find the amount of induced emf generated between 2 wheels if length of excel is 2m . Assuming that vertical component earths magnetic field is 8.0×10⁵ wbpm²
Given :
Speed of train = 108 kmph
Iength of exceI = 2 m b/w 2 wheeIs.
Magnetic fieId of verticaI component earth = 8.0 × 10⁵ wbpm²
To find :
Amount of induced emf generated
SoIution :
⇒ Speed = 108 kmph = 108 × (5/18) = 30 mps
⇔ Induced emf = BIV
Where :
B refers to magnetic fieId component
I refers to Iength of exceI
V refers to veIocity/speed
⇒ Induced emf = 8 × 10⁵ × 2 × 30
⇒ Induced emf = 48,000,000 V
⇒ Induced emf = 48,000 mV
∴ Amount of induced emf generated = 48,000 mV