a train moves in north direction with a speed of 54 km per hour and a monkey running on the roof of the train against its motion with a velocity of 18 km per hour with respect to the train then the velocity of Monkey as observed by a man standing on the ground is
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Answer: 36 kmph Explanation: Given : The velocity of the train set the ground = 54kmph The velocity of monkey wrt train = - 18kmph( negative as the motion is in opposite direction) We know that V(mt) = V(mg) - V(tg) Where V(mt) is the velocity of monkey wrt the train V(mg) is the velocity of monkey wrt the ground V(tg) is the velocity of train wrt the ground V(mg) = V(mt) + V(tg) = -18+54= 36 kmph Therefore the velocity of monkey wrt a ground observer is 36 kmph in the direction of motion of the train , ( i.e) towards North direction. Please mark as Brainliest.
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