A train moves with a speed of 30km/hr in the first 15 min with another speed of 40km/hr in the next 15 min & then with a speed of 60km/hr in the last 30 min. Calculate the average speed of the train for this journey.
Answers
Answer:-
Given:
- A train moves with a speed 30 km/hr in 15 min.
- It moves with a speed of 40 km/hr in other 15 min.
- And, it moves again with a speed of 60 km/h in 30 min.
We know that,
Distance = Speed * Time
• Distance covered when speed of the train was 30 km/h = 30 km/hr * 15 min
1 min = 1/60 hrs
So,
→ Distance covered for the first interval = 30 * 15 * 1/60
→ Distance covered for the first interval = 7.5 km
Similarly,
→ Distance covered for the second interval = 40 * 15 * 1/60
→ Distance covered for the second interval = 10 km
→ Distance covered for the third interval = 60 * 30 * 1/60
→ Distance covered for the third interval = 30 km
We know,
Average speed = Total Distance travelled/total Time taken
• Total Distance travelled = 7.5 + 10 + 30 = 47.5 km
• Total Time taken = 15 + 15 + 30 = 60 min = 1 hr.
→ Average speed of the train = 47.5 / 1
→ Average speed of the train = 47.5 km/hr
Answer:
Given:
A train moves with a speed 30 km/hr in 15 min.
It moves with a speed of 40 km/hr in other 15 min.
And, it moves again with a speed of 60 km/h in 30 min.
We know that,
Distance = Speed * Time
• Distance covered when speed of the train was 30 km/h = 30 km/hr * 15 min
1 min = 1/60 hrs
So,
→ Distance covered for the first interval = 30 * 15 * 1/60
→ Distance covered for the first interval = 7.5 km
Similarly,
→ Distance covered for the second interval = 40 * 15 * 1/60
→ Distance covered for the second interval = 10 km
→ Distance covered for the third interval = 60 * 30 * 1/60
→ Distance covered for the third interval = 30 km
We know,
Average speed = Total Distance travelled/total Time taken
• Total Distance travelled = 7.5 + 10 + 30 = 47.5 km
• Total Time taken = 15 + 15 + 30 = 60 min = 1 hr.
→ Average speed of the train = 47.5 / 1
→ Average speed of the train = 47.5 km/hr
Explanation: