A train moves with a velocity of 30ms^-1 A boy on upper berth drops a ball of mass 100g , the KE of ball with respect to
(i) a person on the ground
(ii) for person sitting in the train at the time of dropping is
(a) 45J ,0J
(b) 0J,45J
(c) 22.5J ,22.5J
(d)45J ,45J
plss answer this fast...
Answers
Answered by
2
Answer :The horizontal range R=
The horizontal range R= g
The horizontal range R= gu
The horizontal range R= gu 2
The horizontal range R= gu 2 sin2θ
The horizontal range R= gu 2 sin2θ
The horizontal range R= gu 2 sin2θ =
The horizontal range R= gu 2 sin2θ = 10
The horizontal range R= gu 2 sin2θ = 10(30)
The horizontal range R= gu 2 sin2θ = 10(30) 2
The horizontal range R= gu 2 sin2θ = 10(30) 2 sin90
The horizontal range R= gu 2 sin2θ = 10(30) 2 sin90
The horizontal range R= gu 2 sin2θ = 10(30) 2 sin90 =90 m
The horizontal range R= gu 2 sin2θ = 10(30) 2 sin90 =90 m(As we measure the distance with respect to the frame of train so velocity of train will not effect on the distance )
Answered by
2
Answer:
c) 22.5J, 22.5J. This is the answer
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