Physics, asked by nithya3322, 7 months ago

A train moves with a velocity of 30ms^-1 A boy on upper berth drops a ball of mass 100g , the KE of ball with respect to
(i) a person on the ground
(ii) for person sitting in the train at the time of dropping is
(a) 45J ,0J
(b) 0J,45J
(c) 22.5J ,22.5J
(d)45J ,45J
plss answer this fast...​

Answers

Answered by neetusinghtrish
2

Answer :The horizontal range R=

The horizontal range R= g

The horizontal range R= gu

The horizontal range R= gu 2

The horizontal range R= gu 2 sin2θ

The horizontal range R= gu 2 sin2θ

The horizontal range R= gu 2 sin2θ =

The horizontal range R= gu 2 sin2θ = 10

The horizontal range R= gu 2 sin2θ = 10(30)

The horizontal range R= gu 2 sin2θ = 10(30) 2

The horizontal range R= gu 2 sin2θ = 10(30) 2 sin90

The horizontal range R= gu 2 sin2θ = 10(30) 2 sin90

The horizontal range R= gu 2 sin2θ = 10(30) 2 sin90 =90 m

The horizontal range R= gu 2 sin2θ = 10(30) 2 sin90 =90 m(As we measure the distance with respect to the frame of train so velocity of train will not effect on the distance )

Answered by pbviveka121
2

Answer:

c) 22.5J, 22.5J. This is the answer

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