a train moves with the constant speed of 36 kmperh with 10 mis and constant speed of 45kmperh with another 10 min and acceleration 5 km/s2 in last 10 minutes find average speed
Answers
Answered by
0
Step-by-step explanation:
Total Distance =(12+8.5+11+8.5+6)=46 km
Total Time =50 min
Average speed =
50
46×60
=55.2km/hr
Answered by
0
Answer:
distance travelled is 921km
speed=36km/h
36×5/18=10m/s
distance=v×t
10×(10×60)=6000m
2nd speed=45km/h
45×5/18=25/2 m/s
distance=25/2×600=7500m
3rd a=5m/s^2
t=600m
v=25m/sec
s=ut+1/2×at^2
=25/2×600+1/2×5×(600)^2
=7500+900000
=907500m
Adding total distance=6000+7500+907500
=921000/1000km
=921km
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