Question

a train moves with the constant speed of 36 kmperh with 10 mis and constant speed of 45kmperh with another 10 min and acceleration 5 km/s2 in last 10 minutes find average speed ​

Answer 1

Step-by-step explanation:

Total Distance =(12+8.5+11+8.5+6)=46 km

Total Time =50 min

Average speed =

50

46×60

=55.2km/hr

Answer 2

Answer:

distance travelled is 921km

speed=36km/h

36×5/18=10m/s

distance=v×t

10×(10×60)=6000m

2nd speed=45km/h

45×5/18=25/2 m/s

distance=25/2×600=7500m

3rd a=5m/s^2

t=600m

v=25m/sec

s=ut+1/2×at^2

=25/2×600+1/2×5×(600)^2

=7500+900000

=907500m

Adding total distance=6000+7500+907500

=921000/1000km

=921km