Question

A train moves with velocity of 54km/h is brought to rest in 5 seconds by applying brakes . find the acceleration and the distance travelled by the train in that time ​

Answer 1

Step-by-step explanation:

Given:

• Initial velocity (u) = 54 km/h = 54 × 1,000/3600 = 15 m/s
• Final velocity (v) = 0 m/s
• Time (t) = 5 seconds

To find:

• Acceleration (a) = ?
• Distance (s) = ?

Solution:

♧ v = u + at ♧

--> 0 = 15 + a × 5

--> -15 = a × 5

--> -15/5 = a

--> -3 m/s^2 = a

▪︎ Hence, acceleration = -3 m/s^2

♧ Distance (s) = u × t + 1/2 × a × (t)^2 ♧

--> 15 × 5 + 1/2 × (-3)× (5)^2

--> 75 + (-1.5) × 25

--> 75 + 37.5

--> 112.5 m

▪︎Hence, the distance traveled = 112.5 meters

Hope this helped you dear...