Question

A Train movie a velocity of 54 km per hour is brought to rest 5 second by our clients find the acceleration product the distance travel by trainit that time

Answer 1

Answer:

u=m/s

t=5s

v=15m/s

a=tv−u=515−5=510

=2m/s2

s=ut+1/2at2

=5×5+1/2×2×52

=25+25

=50m

Explanation:

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