Question

A train moving along a straight track,accelerates from 36km/h to 72km/hin 5 seconds.How much distance does it cover in this time?

Answer 1

Explanation:

UNIT CONVERSION:

initial velocity(in m/s):- 36×5/18= 10m/s

final velocity(in m/s):- 72×5/18= 20m/s

MANAGING DATA:

u = 10m/s

v = 20m/s

t = 5sec

a= ?

FORMULA TO BE USED:

v = u + at

ULTIMATE SOLUTION:

v = u + at

=> 20 = 10 + 5a

=> 20 - 10 = 5a

=> 10 = 5a

=> a = 10/5 => a = 2m (ans)