A train moving at 49 mph meets and is passed by a second train moving at 63 mph. A passenger in the first train noted that the second train took seconds to pass him. How long is the second train?
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Answered by
0
Answer:
740.46ft
Explanation:
162 5289 x (49+63) x 4.5
60 x 60
= 740.46 ft
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Answered by
4
The effective speed between the trains: 49 + 63 = 112 mph
Assume the passenger is stationary and the 2nd train is passing him at 112 mph.
1 mile= 5280 foot.
1 hour= 3600 secs.
(112*5280/3600)*4.5=739.5 ft.
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