Math, asked by ashokmaurya76, 8 months ago

A train moving at 49 mph meets and is passed by a second train moving at 63 mph. A passenger in the first train noted that the second train took seconds to pass him. How long is the second train?​

Answers

Answered by Anonymous
2

&lt;font color="red"&gt;The effective speed between the trains: 49 + 63 = 112 mph</p><p>Assume the passenger is stationary and the 2nd train is passing him at 112 mph.&lt;br&gt;</p><p>1 mile= 5280 foot.&lt;br&gt;</p><p>1 hour= 3600 secs.&lt;br&gt;</p><p>(112*5280/3600)*4.5=739.5 ft.

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Answered by Ronakbhuyan1234540
2

Answer:

here is your answer

Step-by-step explanation:

The effective speed between the trains: 49 + 63 = 112 mph

Assume the passenger is stationary and the 2nd train is passing him at 112 mph.

1 mile= 5280 foot.

1 hour= 3600 secs.

(112*5280/3600)*4.5=739.5 ft.

l hope it's helpful

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