A train moving at a speed of 72kmph towards a station is sounding a whistle of frequency 600Hz. What are the apparent frequencies of the whistle as heard by a man on the platform when the train (1) approaches him (2) recedes from him.....[Given speed of sound in air=340m/s
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Given :
Speed of train=vs=±72kmph= 72x5/18 =±20 m/s
frequency of source =f0=600Hz
Apparent frequency= f.
v = velocity of sound = 340 m/s
velocity of the observer = Vo = 0
f=fo [v±vo]/v±vs
1) Approaches him :
=600x 340+0/ 340-20=637.5Hz
ii) Recedes from him
f= 600 x 340+0/340+20 = 566.6Hz
When the train approaches the frequency increases and it will be less as the train goes away.
This is the Doppler's shift.
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