Question

a train moving at a uniform speed crosses a platform 99m long in 13.5 seconds and an electric pole in 9 seconds. find length​

Answer 1

Step-by-step explanation:

Let the length of the train be x meter.

Train crossed the pole is 2 sec. So distance covered in 2 sec. is x meter.

Hence, the speed of train = distance / time = x / 2 ——- (1)

In second case,

Total distance covered by train is = ( x + 250) meter

Time take = 7 second

So, speed of train = (x + 250 ) / 7 ——(2)

From (1) and (2)

x/2 = (x+250)/7

7x = 2x + 500

5x = 500

x = 100

Hence the length of train is 100m

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let x be the length of train in meters and y be the speed of train in m/s.

now the train passes of length x meters having y speed passes the pole in 2 sec.

therefore…

x/y = 2,

now y=x/2.

and now same train passes the bridge in 7 seconds having length 250m..

now,

(x+250)/7 = y

but y=x/2… therefore..

(x+250/7) = x/2..

solving this we get x=(length of train)=100 m.

Answer 2

The greater of two or the greatest of three dimensions of an object; the length or breadth of something.

The length of the train is 198 meters.

Let's assume that the length of the train is "L" meters and its speed is "v" m/s. Also, let's assume that the distance from the starting point to the electric pole is "d" meters.

When the train passes the platform, it covers the distance of the length of the platform plus the length of the train, which is (L + 99) meters. The time it takes to cover this distance is 13.5 seconds. Therefore, we can write:

$(L + 99) / v = 13.5$

Similarly, when the train passes the electric pole, it covers the distance of the length of the train, which is L meters. The time it takes to cover this distance is 9 seconds. Therefore, we can write:

$L / v = 9$

We can solve these two equations simultaneously to get the values of "L" and "v". First, we can rearrange the second equation to get v in terms of L:

$v = L / 9$

Then, we can substitute this value of v in the first equation and simplify:

$(L + 99) / (L / 9) = 13.5\\9(L + 99) / L = 13.5\\9L + 891 = 13.5L\\4.5L = 891\\L = 198$

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