Question

A train moving toward north is uniformly accelerated from a velocity of 10m/s to 18m/
over a
time of 6.0 seconds. What is the acceleration of the train?​

Answer 1

Explanation:

Initial velocity u=30

i

^

Final velocity v=40

j

^

Change in velocity Δv=40

j

^

−30

i

^

Magnitude ∣Δv∣=

30

2

+40

2

=50

Average acceleration a=

Δt

∣Δv∣

=

10

50

=5 m/s

2