Question

A train moving with a speed of 5 m/s obtains to an acceleration of 0.2 metre per second square. Calculate the speed of the train after 10 seconds, and the distance travelled by it in this time. ​

Answer 1

Answer:

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Explanation:

u = 5 m/sec

a = 0.2 m/sec ^ 2

t = 10 sec

USING 1ST EQ OF MOTION,

v = u + at

v = 5 + 0.2×10

v = 5 + 2

v = 7 m/sec

FINAL VELOCITY = 7 m/sec

2nd EQ OF MOTION,

s = ut + 1/2 at^2

s = 5 × 10 + 1/2 × 2/10×10×10

s = 50 + 10

s = 60m

DISTANCE = 60 m

Answer 2

Explanation: A=V-U/T

=0.2=V-5/10

0.2*10=2

2=V-5

V=2+5=7=FINAL VELOCITY

By using 2nd equation:UT+1/2 AT^2

5*10+1/2 0.2*10^2

50+1/2 0.2*100=50+1/2*20

50+10=60 METERS