Question

A train moving with a speed of 5 m/s obtains to an acceleration of 0.2 metre per second square. Calculate the speed of the train after 10 seconds, and the distance travelled by it in this time.​

Answer 1

Answer:

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Explanation:

u = 5 m/sec

a = 0.2 m/sec ^ 2

t = 10 sec

USING 1ST EQ OF MOTION,

v = u + at

v = 5 + 0.2×10

v = 5 + 2

v = 7 m/sec

FINAL VELOCITY = 7 m/sec

2nd EQ OF MOTION,

s = ut + 1/2 at^2

s = 5 × 10 + 1/2 × 2/10×10×10

s = 50 + 10

s = 60m

DISTANCE = 60 m

Answer 2

Answer:

Kinematics

Explanation:

★ GIVEN ;

» Speed of train ( u ) = 5 m / s

» Acceleration of train ( a ) = 0.2 m / s²

» Time ( t ) = 10 second

» Distance ( s ) = ???

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By Second equation of Motion ;

★ S = ut + 1 / 2 a t² ★

» S = 5 ( 10 ) × 1 / 2 × 0.2 × ( 10 )²

» S = 50 + 0.1 ( 100 )

» S = 50 + 10

★ Distance travelled ( s ) = 60 metres ★