Question

a train moving with a velocity 36km/h us brought to rest applying brakes in 5s . calculate the retardation and distance travelled during this period​

Answer 1

Answer:

• Retardation is 2 m/s².

Distance travelled is 25

Explanation:

To find : Retardation and distance

travelled.

m.

Given that,

Initial velocity, u is 36 km/h. Final velocity, v is 0 km/h

Time, t is 5 s.

We know,

Acceleration = v - u/t

Conversion :

• 35 km/h = (36 x 5)/18 = 10 m/s

. 0 km/h = 0 m/s.

Now, Put values:

→ Acceleration = 0 - 10/5

→ Acceleration = -2

Retardation is negative acceleration.

Thus,

Retardation is 2 m/s².

Now,

We also know,

Second equation of motion :

• s = ut + 1/2 at²

[s is distance travelled]

Put all values:

→s = 10 x 5 + 1/2 × (-2) × (5)² →s = 50 + 1/2 × (-2) × 25 X X

→s 50-50/2

→s = (100-50)/2

→S=25

Thus,

Distance travelled is 25 m.

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Answer 2

Answer:

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