a train moving with a velocity 36km/h us brought to rest applying brakes in 5s . calculate the retardation and distance travelled during this period
Answers
Answer:
• Retardation is 2 m/s².
Distance travelled is 25
Explanation:
To find : Retardation and distance
travelled.
m.
Given that,
Initial velocity, u is 36 km/h. Final velocity, v is 0 km/h
Time, t is 5 s.
We know,
Acceleration = v - u/t
Conversion :
• 35 km/h = (36 x 5)/18 = 10 m/s
. 0 km/h = 0 m/s.
Now, Put values:
→ Acceleration = 0 - 10/5
→ Acceleration = -2
Retardation is negative acceleration.
Thus,
Retardation is 2 m/s².
Now,
We also know,
Second equation of motion :
• s = ut + 1/2 at²
[s is distance travelled]
Put all values:
→s = 10 x 5 + 1/2 × (-2) × (5)² →s = 50 + 1/2 × (-2) × 25 X X
→s 50-50/2
→s = (100-50)/2
→S=25
Thus,
Distance travelled is 25 m.
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Answer:
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