Question

A train moving with a velocity of 36 km/h is accelerated
so that its velocity becomes 90 km/h in 30 seconds.
Find the acceleration of the train.

Answer 1

Answer:

initial velocity - 36 km/h

final velocity - 90 km/h

Time - 30s

so acceleration = final velocity - initial velocity/ time

90-36/30 = 54/30 = 9/5b= 1.8m/s^2

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Answer 2

Given:

Initial velocity = 36 km/hr = 10m/s

Final velocity = 90km/hr = 25m/s

Time = 30 seconds

To Find :

Acceleration of the train

Solution:

by using first equation of motion-

$\huge\bold\red{\mathbb{V=U+AT}}$

we can derive -

a = v-u/t

=> a = 25-10/30

=> a = 15/30

=> a = 0.5 m/s^2

$\boxed{\boxed{\boxed{\mathfrak{a = 0.5m/s^2}}}}$