A train moving with a velocity of 42.9 km/hour North, increases its speed with a uniform acceleration of 0.250 m/s2 North until it reaches a velocity of 160.0 km/hour North. What distance did the train travel while it was increasing its velocity, in units of meters? Give the answer as a positive number
Answers
Answered by
1
Answer:
3672.5m
V=u+at
v---> final velocity =160km/hour =44.5m/s
u---->initial velocity =42.9km/hour=12m/s
a--->acceleration =0.25m/s^2
therefore time t is 130s
Explanation:
Similar questions