Question

A train moving with a velocity of 4m/s begins to accelerate until it reaches a velocity of 10 m/s in 2s.
(a) Find its acceleration
(b) Calculate the distance covered
show your working.

Answer 1

Explanation:

a.u=4m/s

v=10m/s

t=2

on applying equations of motion

v=u+at

10m/s=4m/s+a×2s

6m/s=2s×a

acc.=6÷2

acc.=3m/s²

b. u=4m/s

v=10m/s

t=2

acc.3m/s²

s=ut+1/2at²

s=4×2+1/2×3×2×2

s=8+6

s=14m

Answer 2

Answer:

A=3m/s² d=14m

Explanation:

acceleration =v-u/t

10-4/2=3

Acceleration =3m/s

distance =v²-u²=2as

10²-4²=2*3*s

s=84/6

s=14m