A train moving with acceleration of 4 m/s^2 from rest for 10 seconds find the displacement covered by the train
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26
Answer :
Given that a train moving with acceleration of 4 m/s² from rest for 10 seconds.
We have to find displacement covered by the train.
From the data we have :
Initial speed (u) = 0 m/s [As it starts from rest]
Acceleration (a) = 4 m/s²
Time (t) = 10 s
We know 2nd equation of motion :
→ s = ut + ½ at²
Where,
- s : Displacement
- u : Initial speed
- a : Acceleration
- t : Time
Substituting values,
→ s = 0 × 10 + ½ × 4 × 10²
→ s = 0 + 2 × 100
→ s = 0 + 200
→ s = 200 m
Displacement covered by train = 200 m ✓
Answered by
23
Given :
- Acceleration (a) = 4 m/s²
- Initial velocity (u) = 0 m/s
- Time interval (t) = 10 seconds
To Find :
- Displacement covered by train
Solution :
We're given that a train starts from rest, and it then start moving with the acceleration of 4 m/s² in 10 seconds. We've to calculate displacement travelled by the train.
For this we'll use 2nd equation of motion :
⇒S = ut + ½at²
Where,
- S is displacement
- u is initial velocity
- a is acceleration
- t is time interval
⇒S = 0*10 + ½*4*(10)²
⇒S = 0 + ½*4*100
⇒S = 400/2
⇒S = 200
Displacement of train is 200 m
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