Question

. A train moving with the speed of 30 km per hour travelled from
Kamalapur station to Narayangonj station. If the speed of the train was 25
km per hour, it would take 10 minutes more for the journey. What is the
distance between the two stations ?​

Answer 1

$\sf we~know~that~ \\\\\sf \boxed{Distance=Speed xTime} \\\\\sf$

$\sf Let~ S ~be~ the~ distance ~and ~v ~be~the ~speed ~and~ t~ be ~the ~time \\\\\sf$ $\sf \boxed {Case1} \\\\\sf$

$\sf Now,~ S=vt \\\\\sf S=30t \{i\} \\\\\sf$

$\sf \boxed{case2} \\\\\sf$

$\sf Here, V=25km/hr ~and ~T=t+\frac{1}{6} hr \\\\\sf Now, ~S=25(t+\frac{1}{6}) \{ii\} \\\\\sf Equating ~ \{i\}~ and \{ii\}~, we~get, </p><p>25t+\frac{25}{6}= 30t \\\\\sf 150t+25=180t \\\\\sf 30t=25 \\\\\sf t=\frac{5}{6} \\\\\sf Putting~ the~ value ~of ~\bf{t=\frac{5}{6}}~ in ~ \{i\}, we ~get, \\\\\sf S=30x \frac{5}{6} =25 \\\\\sf$

Distance = 25km